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87 sonuçtan 1-3 arası sonuçlar
Sayfa 668
Then the function equal to the characteristic function xe , e çlo , belongs to PP * (
Qo ) , and the corresponding best approximation is equal to zero for all neN . At
the same time , it does not belong to any of the spaces B . ( Qo ) with a > 1 / p .
Then the function equal to the characteristic function xe , e çlo , belongs to PP * (
Qo ) , and the corresponding best approximation is equal to zero for all neN . At
the same time , it does not belong to any of the spaces B . ( Qo ) with a > 1 / p .
Sayfa 685
Vi = 1 i = 1 It is clear that AUB = lo \ Q and ( An B ) ° = Ø . Further , A is equal to
the union of 2d – 1 intervals R of the form IT - , [ Qi , Bi ] , where ( ai , Bi ] is equal
to [ 0 , ai ] or ( ai , 1 ] . For the given R let | denote the length of the longest edge of
it ...
Vi = 1 i = 1 It is clear that AUB = lo \ Q and ( An B ) ° = Ø . Further , A is equal to
the union of 2d – 1 intervals R of the form IT - , [ Qi , Bi ] , where ( ai , Bi ] is equal
to [ 0 , ai ] or ( ai , 1 ] . For the given R let | denote the length of the longest edge of
it ...
Sayfa 1182
5 ) F [ u ] = 0 , and is equal to Ax + B on a 12 . Proof . We put Ue = AX + B + E (
2x2 – R ? ) , E > 0 . If à is sufficiently large , then , as follows from ( 5 . 1 ) with n =
21 , the function uę is a strong subsolution of ( 4 . 1 ) . Choosing R so that ax ?
5 ) F [ u ] = 0 , and is equal to Ax + B on a 12 . Proof . We put Ue = AX + B + E (
2x2 – R ? ) , E > 0 . If à is sufficiently large , then , as follows from ( 5 . 1 ) with n =
21 , the function uę is a strong subsolution of ( 4 . 1 ) . Choosing R so that ax ?
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İçindekiler
HADAMARDS CONJECTURE | 634 |
Necessary facts about Sobolev spaces | 643 |
Elliptic differential inequalities | 655 |
Telif Hakkı | |
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According algebra analytic apply assertion assume asymptotic Banach space boundary bounded called closed complete condition cone connected Consequently consider const constant construction contains continuous corresponding cubes defined definition denote depend derivatives described determined differential direct domain eigenvalues element English transl equality equation equivalent estimate example exists extension fact field finite fixed follows formula function Further given gives hence holds implies inequality integral introduce lattice Lemma limit linear mapping Math Mathematical matrix means measure multiplicity norm obtained Obviously operator pair particular perturbation polynomial positive possible present principle problem Proof properties Proposition proved reduced relation remains Remark representation respect satisfies scattering side smooth solution space spectral spectrum subspace sufficiently Suppose Theorem theory unique valid vector zero