St. Petersburg Mathematical Journal, 4. cilt,4-6. sayılarAmerican Mathematical Society, 1993 |
Kitabın içinden
89 sonuçtan 1-3 arası sonuçlar
Sayfa 874
... implies numerous metric conditions on E ; see [ 3 ] and [ 6 ] for details . Clearly , the Lebesgue measure of E is equal to 0 . Lemma 2. ( i ) √ , p ( x , E ) −® dx ≤ c | I | 1 - B , B + y < 1 ; therefore p ( x , E ) ß satisfies the ...
... implies numerous metric conditions on E ; see [ 3 ] and [ 6 ] for details . Clearly , the Lebesgue measure of E is equal to 0 . Lemma 2. ( i ) √ , p ( x , E ) −® dx ≤ c | I | 1 - B , B + y < 1 ; therefore p ( x , E ) ß satisfies the ...
Sayfa 1040
... implies 248 ≥ q3 ( q2 – 1 ) and q ≤ 3. But then 31 || L | , a contradiction . Now suppose L = G2 ( q ) . If q ≥ 7 ... implies n ≥ 5 and e ( L ) ≥ q4 - 1 ≥ 255 > 248. If q = 5 , then 215 || L | implies n ≥ 6 and e ( L ) ≥ 55 – 1 ...
... implies 248 ≥ q3 ( q2 – 1 ) and q ≤ 3. But then 31 || L | , a contradiction . Now suppose L = G2 ( q ) . If q ≥ 7 ... implies n ≥ 5 and e ( L ) ≥ q4 - 1 ≥ 255 > 248. If q = 5 , then 215 || L | implies n ≥ 6 and e ( L ) ≥ 55 – 1 ...
Sayfa 1041
... implies m≥ 10 , and hence e ( L ) > ( 210 − 1 ) / 3 > 248. If q = 4 , then 31 || L | implies m ≥ 6 , and hence ≥ e ( L ) ≥ ( 46 − 1 ) / 5 > 248. If 5 ≤ q < 31 , then 31 || L | implies m ≥ 5 , and hence e ( L ) ≥ 5 ( 54 − 1 ) ...
... implies m≥ 10 , and hence e ( L ) > ( 210 − 1 ) / 3 > 248. If q = 4 , then 31 || L | implies m ≥ 6 , and hence ≥ e ( L ) ≥ ( 46 − 1 ) / 5 > 248. If 5 ≤ q < 31 , then 31 || L | implies m ≥ 5 , and hence e ( L ) ≥ 5 ( 54 − 1 ) ...
İçindekiler
MATHEMATICS | 665 |
150 | 832 |
ABSTRACT Let be an elliptic differential operator of order n2 with constant | 940 |
Telif Hakkı | |
4 diğer bölüm gösterilmiyor
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a₁ analytic assertion assume asymptotic Blaschke product boundary bounded C₁ cone consider const constant construction convex corresponding covector cubes D₁ decomposition defined definition denote diffeomorphisms differential domain eigenvalues English transl equality equation equivalent estimate exists finite follows function f H₁ hence Hilbert space Hölder holds inequality inner function integral irreducible lattice Lemma Leningrad Lie algebra linear M₁ mapping Mathematical Mathematics Subject Classification maximum principle morphism multiplicity nonlinear norm obtained operator pair perturbation polynomial problem proof of Theorem properties Proposition proved representation Riemann-Roch theorem S₁ satisfying the conditions scattering matrix scattering theory selfadjoint singular smooth solution Soviet Math space spectral spectrum Steklov subspace sufficiently Suppose t₁ Theorem 1.1 theory trace formula trace-class unique unitary V₁ zero