St. Petersburg Mathematical Journal, 4. cilt,4-6. sayılarAmerican Mathematical Society, 1993 |
Kitabın içinden
90 sonuçtan 1-3 arası sonuçlar
Sayfa 874
... implies numerous metric conditions on E ; see [ 3 ] and [ 6 ] for details . Clearly , the Lebesgue measure of E is equal to 0 . Lemma 2. ( i ) √ , p ( x , E ) −3 dx ≤ c | I | 1 − ß , ß + y < 1 ; therefore p ( x , E ) ß satisfies the ...
... implies numerous metric conditions on E ; see [ 3 ] and [ 6 ] for details . Clearly , the Lebesgue measure of E is equal to 0 . Lemma 2. ( i ) √ , p ( x , E ) −3 dx ≤ c | I | 1 − ß , ß + y < 1 ; therefore p ( x , E ) ß satisfies the ...
Sayfa 1040
... implies 248 ≥ q3 ( q2 – 1 ) and q ≤ 3. But then 31 || L | , a contradiction . Now suppose L = G2 ( q ) . If q≥ 7 ... implies n ≥ 5 and e ( L ) ≥ q4 − 1 > 255 > 248. If q = 5 , then 215 || L | implies n ≥ 6 and e ( L ) ≥ 55 – 1 ...
... implies 248 ≥ q3 ( q2 – 1 ) and q ≤ 3. But then 31 || L | , a contradiction . Now suppose L = G2 ( q ) . If q≥ 7 ... implies n ≥ 5 and e ( L ) ≥ q4 − 1 > 255 > 248. If q = 5 , then 215 || L | implies n ≥ 6 and e ( L ) ≥ 55 – 1 ...
Sayfa 1041
... implies m≥ 10 , and hence e ( L ) ≥ ( 210 − 1 ) / 3 > 248. If q = 4 , then 31 || L | implies m > 6 , and hence e ( L ) ≥ ( 46 − 1 ) / 5 > 248. If 5 ≤ q < 31 , then 31 || L | implies m ≥ 5 , and hence e ( L ) ≥ 5 ( 54 − 1 ) / 6 > ...
... implies m≥ 10 , and hence e ( L ) ≥ ( 210 − 1 ) / 3 > 248. If q = 4 , then 31 || L | implies m > 6 , and hence e ( L ) ≥ ( 46 − 1 ) / 5 > 248. If 5 ≤ q < 31 , then 31 || L | implies m ≥ 5 , and hence e ( L ) ≥ 5 ( 54 − 1 ) / 6 > ...
İçindekiler
HADAMARDS CONJECTURE | 634 |
1993 No 4 | 921 |
AND ESTIMATES OF THE GREEN FUNCTION | 1054 |
Telif Hakkı | |
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According algebra analytic apply assertion assume asymptotic boundary bounded closed complete condition cone connected Consequently consider const constant construction contains continuous corresponding cubes defined definition denote depend derivatives described determined differential domain eigenvalues element English transl equality equation equivalent estimate example exists extension fact field finite fixed follows formula function given gives hence holds implies inequality integral introduce Lemma limit linear mapping Math Mathematical means measure multiplicity norm obtained Obviously operator pair particular perturbation positive possible principle problem Proof properties Proposition proved reduced relation remains Remark representation respect satisfies scattering side smooth solution space spectral spectrum subspace sufficiently Suppose Theorem theory unique vector zero