St. Petersburg Mathematical Journal, 12. cilt,507-1059. sayfalarAmerican Mathematical Society, 2001 |
Kitabın içinden
77 sonuçtan 1-3 arası sonuçlar
Sayfa 641
... easily seen that whence ( 126 ) Sq2 ( wm U & Sqn Xn ) = wmU & Sq2 82n Kn 82 Sq2 ( wmU & 82n Xn ) \ m > n = ( 0,0,0,1 \ m > n › 0 ) . Finally , from ( 123 ) , ( 125 ) , and ( 126 ) we obtain ( 127 ) 82 Sq2 ( a ) → ( 2 ′′ -1m < n ; 0,1 ...
... easily seen that whence ( 126 ) Sq2 ( wm U & Sqn Xn ) = wmU & Sq2 82n Kn 82 Sq2 ( wmU & 82n Xn ) \ m > n = ( 0,0,0,1 \ m > n › 0 ) . Finally , from ( 123 ) , ( 125 ) , and ( 126 ) we obtain ( 127 ) 82 Sq2 ( a ) → ( 2 ′′ -1m < n ; 0,1 ...
Sayfa 653
... easily be proved by using the map transversality theorem ( valid in all dimensions [ 10 ] , which was not known when [ 7 ] appeared ) , and a generalization of the Rokhlin theorem , namely , the relation ( 159 ) P160 ( M ) = 18 △ ( M ) ...
... easily be proved by using the map transversality theorem ( valid in all dimensions [ 10 ] , which was not known when [ 7 ] appeared ) , and a generalization of the Rokhlin theorem , namely , the relation ( 159 ) P160 ( M ) = 18 △ ( M ) ...
Sayfa 676
... easily be deduced from the information we have about the classes a and d . Indeed , by Subsection 5.6 , we have ( a ) = 6 ( and , of course , △ ( a ) = 0 ) , and ( 235 ) follows . Next , by Subsection 5.7 , we have the relations ( d ) ...
... easily be deduced from the information we have about the classes a and d . Indeed , by Subsection 5.6 , we have ( a ) = 6 ( and , of course , △ ( a ) = 0 ) , and ( 235 ) follows . Next , by Subsection 5.7 , we have the relations ( d ) ...
İçindekiler
SH BIRMAN A LAPTEV AND T A SUSLINA | 536 |
2 Formulation of the main results | 543 |
4 Proof of Theorem 2 3 beginning | 551 |
Telif Hakkı | |
6 diğer bölüm gösterilmiyor
Diğer baskılar - Tümünü görüntüle
Sık kullanılan terimler ve kelime öbekleri
algebra apply arbitrary assume asymptotic axes axis base belongs boundary bounded called coincides compact complete condition consequence consider constant construction contains continuous corresponding defined definition denote depend described determined dimension disks element English transl equal equation equivalent estimate exists exponential extension fiber field Figure finite fixed formula function given graph Hence homomorphism identity implies inequality integral introduce invariant isomorphism Lemma manifold Math Mathematical neighborhood obtain operator positive problem projection Proof Proposition proved quadratic form recall regular relation remains Remark representation respectively restriction satisfies semigroup sequence side similar simple smooth solution space spectrum Sq² statement Subsection suffices Suppose Theorem theory transformation trivial true values variation vector weight zero