St. Petersburg Mathematical Journal, 11. cilt,1-542. sayfalarAmerican Mathematical Society, 2000 |
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44 sonuçtan 1-3 arası sonuçlar
Sayfa 432
... isomorphism . Now , using the isomorphisms ã , and ( az ) * ( for all ME Do ) and arguing in a standard way , we prove that there is an isomorphism X : V → TOZ with azλ = a . Hence , in diagram ( 3.13 ) we can replace the object V by ...
... isomorphism . Now , using the isomorphisms ã , and ( az ) * ( for all ME Do ) and arguing in a standard way , we prove that there is an isomorphism X : V → TOZ with azλ = a . Hence , in diagram ( 3.13 ) we can replace the object V by ...
Sayfa 436
... isomorphism for each A C1 . Since Xo , Yo e C , it readily follows that fo is an isomorphism . Now , let a morphism q = fs : XY in the category D / C be represented by a diagram X ZY with sЄ S. We put j × ( q ) = fos1 . Clearly , j . is ...
... isomorphism for each A C1 . Since Xo , Yo e C , it readily follows that fo is an isomorphism . Now , let a morphism q = fs : XY in the category D / C be represented by a diagram X ZY with sЄ S. We put j × ( q ) = fos1 . Clearly , j . is ...
Sayfa 439
... isomorphism ( we use Remark 4.1a ) ) . Since j , j are fully faithful , it follows that ŋ and n ' are natural equivalences . Thus , a = nAi * ( h ) : i * X → A is an isomorphism . We prove that there exists an isomorphism B : j * XB ...
... isomorphism ( we use Remark 4.1a ) ) . Since j , j are fully faithful , it follows that ŋ and n ' are natural equivalences . Thus , a = nAi * ( h ) : i * X → A is an isomorphism . We prove that there exists an isomorphism B : j * XB ...
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