Kitabın içinden
56 sonuçtan 1-3 arası sonuçlar
Sayfa 650
13 each time Eg in two possible ways , we obtain the arrangements in Figure 16 .
n for n = 1 , 2 , 6 , 7 , 13 , 14 , 15 , 16 , 19 , 20 , 21 , 22 as follows : | 16 . 15 18 . 1
→ J 16 . 1 16 . 6 18 . 2 → 18 . 3 → 16 . 16 16 . 2 | 16 . 7 ( 16 . 21 18 . 4 + 18 .
13 each time Eg in two possible ways , we obtain the arrangements in Figure 16 .
n for n = 1 , 2 , 6 , 7 , 13 , 14 , 15 , 16 , 19 , 20 , 21 , 22 as follows : | 16 . 15 18 . 1
→ J 16 . 1 16 . 6 18 . 2 → 18 . 3 → 16 . 16 16 . 2 | 16 . 7 ( 16 . 21 18 . 4 + 18 .
Sayfa 652
Let x = xo , . . . , X = X4 be the equations of the lines P ' , Q1 , Q2 , Q3 , Q4 ,
respectively ( see Figure 22 . 5 ) . As was shown in [ 22 , Lemma 3 . 7 ] , a3 ( x )
has at least 2 | k | – 1 roots in the segment ( 22 , X3 ) , and k = - 3 by Lemma 4 . 1 .
Let x = xo , . . . , X = X4 be the equations of the lines P ' , Q1 , Q2 , Q3 , Q4 ,
respectively ( see Figure 22 . 5 ) . As was shown in [ 22 , Lemma 3 . 7 ] , a3 ( x )
has at least 2 | k | – 1 roots in the segment ( 22 , X3 ) , and k = - 3 by Lemma 4 . 1 .
Sayfa 656
on TM cat o FIGURE 27 . 1 . ( 6 - 7 ) . FIGURE 27 . 2 . ( 18 - 5 ) . Proof . It is easy to
check that the braid b defined in Subsection 4 . 1 is trivial for k = - 3 . Indeed , 6 - 1
= A - 2801030203010201 40201 = A - 280103 ( 610302030102 ) 0201071 ...
on TM cat o FIGURE 27 . 1 . ( 6 - 7 ) . FIGURE 27 . 2 . ( 18 - 5 ) . Proof . It is easy to
check that the braid b defined in Subsection 4 . 1 is trivial for k = - 3 . Indeed , 6 - 1
= A - 2801030203010201 40201 = A - 280103 ( 610302030102 ) 0201071 ...
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İçindekiler
A Brudnyi and D Kinzebulatov Uniform subalgebras of 1 on the unit | 495 |
N A Vavilov Can one see the signs of structure constants? | 519 |
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Sık kullanılan terimler ve kelime öbekleri
algebra arrangements assume base belong bundle called character Chevalley closed coefficients commutative complete condition consider constant construction contains continuous Corollary corresponding curve defined definition denote determined diagram direct elementary elements embedding equal equation equivalent example exists extension fact field FIGURE finite fixed formula function given Hence homogeneous homomorphism ideal identity implies inequality integer introduce inverse irreducible isomorphism Lemma linear Math Mathematical matrix maximal means module Moreover multiplication natural nonzero normal Note objects obtain operator particular permutation points polynomial positive present prime problem projective Proof properties Proposition prove Providence Recall relations Remark representation respectively result ring root satisfies scheme sequence similar solution space statement structure subgroup subset Suppose Theorem theory values variety vector weight