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39 sonuçtan 1-3 arası sonuçlar
Sayfa 587
The first inequality follows from item 2) of Lemma 4 (which is applicable because
of (24)); the last inequality is a consequence of (20). The inequality |/„(x)| < ||/„+i(x
)| follows from the above estimate if 2c(a)\(36~lp~1 < A. If £ G„+1, then the same ...
The first inequality follows from item 2) of Lemma 4 (which is applicable because
of (24)); the last inequality is a consequence of (20). The inequality |/„(x)| < ||/„+i(x
)| follows from the above estimate if 2c(a)\(36~lp~1 < A. If £ G„+1, then the same ...
Sayfa 939
Thus, (4) Xo(l) < 2ak(L), where xo is an irreducible greatest degree character of L
and a = | Out(L)|. By Lemma 2(i), we have k{G/M) < Therefore, we can replace the
constant 2m by 3m/2 in inequality (2). The resulting inequality takes the form ...
Thus, (4) Xo(l) < 2ak(L), where xo is an irreducible greatest degree character of L
and a = | Out(L)|. By Lemma 2(i), we have k{G/M) < Therefore, we can replace the
constant 2m by 3m/2 in inequality (2). The resulting inequality takes the form ...
Sayfa 976
... explicitly) such that the characteristic function h(I,m) of the ideal I satisfies the
inequality (1) h(I,m) < n2'C desmn-\ m > 1. The proof of this theorem involves the
author's results from [4, 5] and inequality (2) , which is interesting by itself.
Namely ...
... explicitly) such that the characteristic function h(I,m) of the ideal I satisfies the
inequality (1) h(I,m) < n2'C desmn-\ m > 1. The proof of this theorem involves the
author's results from [4, 5] and inequality (2) , which is interesting by itself.
Namely ...
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İçindekiler
A Brudnyi and D Kinzebulatov Uniform subalgebras of L00 on the unit | 495 |
N A Vavilov Can one see the signs of structure constants? | 519 |
Waldemar Holubowski A new measure of growth for groups and algebras | 545 |
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