St. Petersburg Mathematical Journal, 19. cilt,495-765. sayfalarAmerican Mathematical Society, 2008 |
Kitabın içinden
85 sonuçtan 1-3 arası sonuçlar
Sayfa 646
... obtain an arrangement of an M - quartic with respect to four lines as in Figure 15.1 . III II A2 II P2 IV Pi IV P3 P2 IV Pi Q A2 0000 P3 III II FIGURE 15.1 III FIGURE 15.2 II FIGURE 15.3 FIGURE 15.4 Applying the birational quadratic ...
... obtain an arrangement of an M - quartic with respect to four lines as in Figure 15.1 . III II A2 II P2 IV Pi IV P3 P2 IV Pi Q A2 0000 P3 III II FIGURE 15.1 III FIGURE 15.2 II FIGURE 15.3 FIGURE 15.4 Applying the birational quadratic ...
Sayfa 650
... obtain an arrangement as in Figure 22.2 . Rotating L2 around q ' as shown in Figure 22.2 , we obtain Figure 22.3 , where RP2 is depicted as a disk with opposite boundary points identified . The boundary of the disk represents L1 ...
... obtain an arrangement as in Figure 22.2 . Rotating L2 around q ' as shown in Figure 22.2 , we obtain Figure 22.3 , where RP2 is depicted as a disk with opposite boundary points identified . The boundary of the disk represents L1 ...
Sayfa 780
... obtain the following system of relations : -- go = a1 a . · Nao , 91 + ago = . 2a2 - a ( N - 1 ) a1 , 92 + agi 3a3 ... obtain p | N , whence gi = ( i + 1 ) ai + 1 , i = 0 , 1 , ... , N - 2 . ( 3 ) ( 4 ) = Next , comparing forms of degree ...
... obtain the following system of relations : -- go = a1 a . · Nao , 91 + ago = . 2a2 - a ( N - 1 ) a1 , 92 + agi 3a3 ... obtain p | N , whence gi = ( i + 1 ) ai + 1 , i = 0 , 1 , ... , N - 2 . ( 3 ) ( 4 ) = Next , comparing forms of degree ...
İçindekiler
A Brudnyi and D Kinzebulatov Uniform subalgebras of L on the unit | 495 |
N A Vavilov Can one see the signs of structure constants? | 519 |
Waldemar Hołubowski A new measure of growth for groups and algebras | 545 |
Telif Hakkı | |
27 diğer bölüm gösterilmiyor
Diğer baskılar - Tümünü görüntüle
Sık kullanılan terimler ve kelime öbekleri
algebra arrangements assume automorphism base belong called character closed coefficients commutative complete condition Consequently consider constant construction contains continuous corresponding curve defined definition denote determined direct elementary elements equal equation equivalent example exists extension fact field Figure finite fixed formula function given gives Hence homogeneous homomorphism ideal implies inequality integer introduce inverse irreducible isomorphism Lemma linear Math Mathematical matrices means module Moreover multiplication natural normal Note objects obtain operator particular permutation points polynomial positive present prime problem projective Proof properties Proposition prove relations Remark representation respectively result ring root satisfies scheme sequence similar simple solution space statement structure subgroup subset suffices Suppose Theorem theory tree values variety vector weight