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78 sonuçtan 1-3 arası sonuçlar
Sayfa 81
( ii ) The spaces K . ( H ) and 11 ( H ) are Montel ( consequently , reflexive ) . ( iii )
The strong dual of K . ( H ) can be identified with 11 ( H ) with the help of the
mapping 9H ( ( e ( k ) ) ) ken . The spaces Ko ( H ) and A1 ( H ) are put in duality
via the ...
( ii ) The spaces K . ( H ) and 11 ( H ) are Montel ( consequently , reflexive ) . ( iii )
The strong dual of K . ( H ) can be identified with 11 ( H ) with the help of the
mapping 9H ( ( e ( k ) ) ) ken . The spaces Ko ( H ) and A1 ( H ) are put in duality
via the ...
Sayfa 436
1 , Eu ( t , 1 ) = const on ( a , ) for any fixed 1 € C . Consequently , fj ( t ) EC % ' ( I )
. If , moreover , ( a , ) is the left exceptional interval , then , by Lemma 2 . 2 , on it
we have Emfj ( t ) = * ( t ) = 0 . Thus , fj E Lx . Since the set L , is closed in c # ' ( I )
...
1 , Eu ( t , 1 ) = const on ( a , ) for any fixed 1 € C . Consequently , fj ( t ) EC % ' ( I )
. If , moreover , ( a , ) is the left exceptional interval , then , by Lemma 2 . 2 , on it
we have Emfj ( t ) = * ( t ) = 0 . Thus , fj E Lx . Since the set L , is closed in c # ' ( I )
...
Sayfa 441
Consequently , if fi ( t ) differs from zero at one point in ( a , b ) , then so it does at
all points of that interval , i = 1 , 2 . Proof . One of two situations is possible : either
fı ( t ) = 0 for all t E ( a , b ) , or fi ( t ) # 0 for at least one point t E ( a , b ) .
Consequently , if fi ( t ) differs from zero at one point in ( a , b ) , then so it does at
all points of that interval , i = 1 , 2 . Proof . One of two situations is possible : either
fı ( t ) = 0 for all t E ( a , b ) , or fi ( t ) # 0 for at least one point t E ( a , b ) .
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero