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19 sonuçtan 1-3 arası sonuçlar
Sayfa 178
... Bulletin of the American Mathematical Society Mathematics of Computation
Conformal Geometry and Dynamics » Proceedings of the American Mathematical
Society Electronic Research Announcements » Representation Theory > Journal
...
... Bulletin of the American Mathematical Society Mathematics of Computation
Conformal Geometry and Dynamics » Proceedings of the American Mathematical
Society Electronic Research Announcements » Representation Theory > Journal
...
Sayfa 263
Since | ( Um , 1 QUm , 1 , U ) | < | | Um , 1 | 13 | | U | | = | | U | | , in this case we see
that \ U ( 0 ) | < | | U1 | If Enso 11 / 200 - 2 ( n ) is divergent , a similar computation
shows that lim infm - \ U ( X ) – ( u mnt um , , U ) ] = 0 , and again we get JŪ ( X ) ...
Since | ( Um , 1 QUm , 1 , U ) | < | | Um , 1 | 13 | | U | | = | | U | | , in this case we see
that \ U ( 0 ) | < | | U1 | If Enso 11 / 200 - 2 ( n ) is divergent , a similar computation
shows that lim infm - \ U ( X ) – ( u mnt um , , U ) ] = 0 , and again we get JŪ ( X ) ...
Sayfa 483
... to the equations ( 3 . 1 ) ( 3 . 2 ) dj per ( 1 ) = 2 , dj per ( a ) = - 2 ( respectively ) .
As was mentioned in 81 , J is never semibounded if M and N are odd . In what
follows we consider three cases . a ) M = 1 , N = 2 . Direct computation shows that
...
... to the equations ( 3 . 1 ) ( 3 . 2 ) dj per ( 1 ) = 2 , dj per ( a ) = - 2 ( respectively ) .
As was mentioned in 81 , J is never semibounded if M and N are odd . In what
follows we consider three cases . a ) M = 1 , N = 2 . Direct computation shows that
...
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero