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83 sonuçtan 1-3 arası sonuçlar
Sayfa 181
Suppose that o is logarithmically concave , i . e . , on - 1 ) o ( n + 1 ) < o ( n ) , and
that limn ~ + 00 O ( n ) = 0 . Then equation ( 2 ) has no solutions . Proof . Fix u and
v satisfying ( 2 ) , u ( 0 ) + 0 , and consider the S - 1 - invariant subspace E of l ?
Suppose that o is logarithmically concave , i . e . , on - 1 ) o ( n + 1 ) < o ( n ) , and
that limn ~ + 00 O ( n ) = 0 . Then equation ( 2 ) has no solutions . Proof . Fix u and
v satisfying ( 2 ) , u ( 0 ) + 0 , and consider the S - 1 - invariant subspace E of l ?
Sayfa 239
1 ) First , we consider Rp2k + 1 . If y , z E RP2k + 1 are distinct , then let l ( y , z )
denote the line containing them , and let C = Urek Rl ( p , x ) . If p is a generic
point , then the cone C is an immersed submanifold , except possibly at p (
because ...
1 ) First , we consider Rp2k + 1 . If y , z E RP2k + 1 are distinct , then let l ( y , z )
denote the line containing them , and let C = Urek Rl ( p , x ) . If p is a generic
point , then the cone C is an immersed submanifold , except possibly at p (
because ...
Sayfa 357
... valid ( together with all their consequences below ) for an arbitrary function ( or
class of functions ) for which the one - dimensional result is true . For instance ,
instead of polynomials of degree d , we may consider exponential polynomials of
...
... valid ( together with all their consequences below ) for an arbitrary function ( or
class of functions ) for which the one - dimensional result is true . For instance ,
instead of polynomials of degree d , we may consider exponential polynomials of
...
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero