St. Petersburg Mathematical Journal, 14. cilt,1-534. sayfalarAmerican Mathematical Society, 2003 |
Kitabın içinden
90 sonuçtan 1-3 arası sonuçlar
Sayfa 11
... estimate in the strip On the other hand , from Step 1 it follows that u ( x , -∞ ) This yields the desired estimate for u in R2 { 0 < x < ε } is obvious . - Step 4. Now we prove ( 20 ) , assuming that a = 0 , as before . The proof is ...
... estimate in the strip On the other hand , from Step 1 it follows that u ( x , -∞ ) This yields the desired estimate for u in R2 { 0 < x < ε } is obvious . - Step 4. Now we prove ( 20 ) , assuming that a = 0 , as before . The proof is ...
Sayfa 128
... estimate by O ( 1-1 / 2f ( 1 ) ) . In- deed , relations ( 1.1.20 ) and ( 1.1.21 ) imply that 1 sin2 kn F cos kn kn sin3 kn = 1 2 sin2 kn · 0 ( 1−1 / 2ƒ ( 1 ) ) . Differentiating the remaining terms , we improve the preceding estimate ...
... estimate by O ( 1-1 / 2f ( 1 ) ) . In- deed , relations ( 1.1.20 ) and ( 1.1.21 ) imply that 1 sin2 kn F cos kn kn sin3 kn = 1 2 sin2 kn · 0 ( 1−1 / 2ƒ ( 1 ) ) . Differentiating the remaining terms , we improve the preceding estimate ...
Sayfa 357
... estimate ( R ) : the only difference is that instead of the maximum over the entire set F , we have the " median " M ( P ) on the left - hand side . We want to emphasize here that the comparison lemma and both distribution inequali ...
... estimate ( R ) : the only difference is that instead of the maximum over the entire set F , we have the " median " M ( P ) on the left - hand side . We want to emphasize here that the comparison lemma and both distribution inequali ...
İçindekiler
Китаев А В Специальные функции изомонодромного типа ра | 121 |
Набоко С Н Янас Я Критерии полуограниченности в одном | 158 |
Пажитнов А В О замкнутых орбитах градиентных потоков ото | 186 |
Telif Hakkı | |
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Sık kullanılan terimler ve kelime öbekleri
algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined domain element equal equation equivalence estimate exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space statement Subsection suffices Suppose takes Theorem theory transformation true twists vector weight zero