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68 sonuçtan 1-3 arası sonuçlar
Sayfa 11
This yields the desired estimate for u in R ? n { t < 0 } . The same estimate in the
strip { 0 < x < € } is obvious . Step 4 . Now we prove ( 20 ) , assuming that a = 0 ,
as before . The proof is the same as in Lemma 1 . 4 with t° = 0 . The only
difference ...
This yields the desired estimate for u in R ? n { t < 0 } . The same estimate in the
strip { 0 < x < € } is obvious . Step 4 . Now we prove ( 20 ) , assuming that a = 0 ,
as before . The proof is the same as in Lemma 1 . 4 with t° = 0 . The only
difference ...
Sayfa 128
1 . 27 ) 20 = exp ( - dn ao = exp 1 - Ino 1 + 2 + 1 " on ) , where no is a lower bound
for 11 . We assume that the constant up to which ao is defined is equal to 1 .
Using estimates ( 1 . 1 . 26 ) and the inequalities ( 1 . 1 . 28 ) ka ' s ci - 1 , sin
handsc ...
1 . 27 ) 20 = exp ( - dn ao = exp 1 - Ino 1 + 2 + 1 " on ) , where no is a lower bound
for 11 . We assume that the constant up to which ao is defined is equal to 1 .
Using estimates ( 1 . 1 . 26 ) and the inequalities ( 1 . 1 . 28 ) ka ' s ci - 1 , sin
handsc ...
Sayfa 357
The second distribution inequality resembles a lot the classical Remez estimate (
R ) : the only difference is that instead of the maximum over the entire set F , we
have the “ median " M ( P ) on the left - hand side . We want to emphasize here ...
The second distribution inequality resembles a lot the classical Remez estimate (
R ) : the only difference is that instead of the maximum over the entire set F , we
have the “ median " M ( P ) on the left - hand side . We want to emphasize here ...
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero