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33 sonuçtan 1-3 arası sonuçlar
Sayfa 244
vectors in TRP3K that are tangent to C and orthogonal to the tangent vector of K )
. Since c is generic , vK is a 1 - dimensional subbundle of the 2 - dimensional
bundle NK . Let EK denote the orthogonal complement of vK in NK . We easily
see ...
vectors in TRP3K that are tangent to C and orthogonal to the tangent vector of K )
. Since c is generic , vK is a 1 - dimensional subbundle of the 2 - dimensional
bundle NK . Let EK denote the orthogonal complement of vK in NK . We easily
see ...
Sayfa 434
1 ) also implies that if ß < oo , then a VVFgEL ( a , b ) is orthogonal to ĉ 2 ) ( a , b )
if and only if ( 3 . 3 ) E * g ( t ) dt = 0 . Ja Suppose I admits at least one H - i . i .
Two different maximal H - i . i . ' s cannot have a common inner point . Thus , the
set ...
1 ) also implies that if ß < oo , then a VVFgEL ( a , b ) is orthogonal to ĉ 2 ) ( a , b )
if and only if ( 3 . 3 ) E * g ( t ) dt = 0 . Ja Suppose I admits at least one H - i . i .
Two different maximal H - i . i . ' s cannot have a common inner point . Thus , the
set ...
Sayfa 489
... operator Q : f f commutes with the operators of the adjoint action , then Q is
proportional to the identity operator ( see ( 2 ] ) . Therefore , for some constants ci
( cı = 1 ) we have s = { ( cıx , C2X , . . . , Cnx ) } xEf . Since ő is ( : , - ) - orthogonal
to h ...
... operator Q : f f commutes with the operators of the adjoint action , then Q is
proportional to the identity operator ( see ( 2 ] ) . Therefore , for some constants ci
( cı = 1 ) we have s = { ( cıx , C2X , . . . , Cnx ) } xEf . Since ő is ( : , - ) - orthogonal
to h ...
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero