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37 sonuçtan 1-3 arası sonuçlar
Sayfa 244
vectors in TRP3\x that are tangent to C and orthogonal to the tangent vector of K).
Since c is generic, vK is a 1-dimensional subbundle of the 2-dimensional bundle
NK . Let £K denote the orthogonal complement of vK in NK. We easily see that ...
vectors in TRP3\x that are tangent to C and orthogonal to the tangent vector of K).
Since c is generic, vK is a 1-dimensional subbundle of the 2-dimensional bundle
NK . Let £K denote the orthogonal complement of vK in NK. We easily see that ...
Sayfa 391
It is specific for the series that two possibilities arise (depending on whether N is
odd or even) in the last but one step of a maximal chain of twists: 0 o- -o or o- 0 o
0 The first diagram corresponds to an even-odd orthogonal algebra, and the ...
It is specific for the series that two possibilities arise (depending on whether N is
odd or even) in the last but one step of a maximal chain of twists: 0 o- -o or o- 0 o
0 The first diagram corresponds to an even-odd orthogonal algebra, and the ...
Sayfa 489
Since p is (•, )-orthogonal to hj = {(x, . . . , x)}x6f, it follows that Yl7=i Ci = ^-
Consequently, we can put (C!,C2, . . . ,cn) a = , : — . U Remark. We have used the
obvious fact that two modules pi = {(aiX,Q2x, ...,a„x)}xef and p2 = {(ftx.&x, . . . ,/?„x
)}x€{ ...
Since p is (•, )-orthogonal to hj = {(x, . . . , x)}x6f, it follows that Yl7=i Ci = ^-
Consequently, we can put (C!,C2, . . . ,cn) a = , : — . U Remark. We have used the
obvious fact that two modules pi = {(aiX,Q2x, ...,a„x)}xef and p2 = {(ftx.&x, . . . ,/?„x
)}x€{ ...
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algebraic analytic apply assume basis boundary bounded called chain homotopy closed coefficients complex computation condition connection Consequently consider constant construction contains continuous convex corresponding defined definition deformation denote determined differential domain element equal equation equivalence estimate example exists extension fact field finite fixed formula function given identity implies inequality integral intersection introduce invariant inverse isomorphism Lemma linear Math Mathematical matrix measure metric Moreover natural normal Observe obtain Obviously operator orientation particular periodic positive present problem projective Proof properties Proposition prove regular relation Remark respectively result ring satisfies scheme sequence singular smooth solutions space standard statement Subsection suffices Suppose takes Theorem theory transformation true twists unique vector weight zero